What is the equation of the line with slope # m= 3/5 # that passes through # (-2,17) #?
5y - 3x - 91 = 0
Writing the equation in the form y = mx + c , where m represents the gradient (slope) and c, the y-intercept.
Using (-2,17) to find c , by substituting x = -2 , y = 17 into the equation.
multiplying through by 5 , will eliminate fractions.
hence : 5y = 3x + 91 → 5y - 3x - 91 = 0
All 3 forms are valid equations for the line.
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The equation of the line with slope ( m = \frac{3}{5} ) that passes through the point ( (-2,17) ) is:
[ y - y_1 = m(x - x_1) ]
Substituting the values ( m = \frac{3}{5} ), ( x_1 = -2 ), and ( y_1 = 17 ):
[ y - 17 = \frac{3}{5}(x - (-2)) ]
[ y - 17 = \frac{3}{5}(x + 2) ]
[ y - 17 = \frac{3}{5}x + \frac{6}{5} ]
[ y = \frac{3}{5}x + \frac{6}{5} + 17 ]
[ y = \frac{3}{5}x + \frac{6}{5} + \frac{85}{5} ]
[ y = \frac{3}{5}x + \frac{91}{5} ]
Therefore, the equation of the line is ( y = \frac{3}{5}x + \frac{91}{5} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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