What is the equation of the line with slope -2/3 and passes through the point (3, 2)?

Answer 1

The equation of the line in slope-intercept form becomes

#y = -2/3 x + 4#

The slope intercept form of a line is #y=mx+b#
For this problem we are given the slope as #-2/3# and a point on the line of #(3,2)#
#m=-2/3# #x=3# #y=2#
We plug in the values and then solve for the #b# term which is the y-intercept.
#2 =-2/3(3) +b#
#2 =-2 +b#
Now isolate the #b# term.
#2 +2 =cancel(-2) cancel(+2)+b#
#b= 4#

The equation of the line in slope-intercept form becomes

#y = -2/3 x + 4#
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Answer 2

The equation of the line with slope -2/3 and passing through the point (3, 2) is y = (-2/3)x + 8/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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