What is the equation of the line the passes through the points (6, 8) and (12, 4)?

Answer 1

#y=-2/3x+12#

First step is to find the slope.

You do this by using the formula:

#m = (y_1 - y_2) / (x_1 - x_2)#

You can use the two points you are given. It doesn't mater which points you use first as long as the y goes on the top and the x on the bottom and keep the point together

#m = (8 -4) / (6 -12)#

#m = (4) / (-6)#

#m =- (2) / (3)#

#m = (4-8) / (12-6)#

#m = (-4) / (6)#

#m =- (2) / (3)#

Now that you have the slope you almost completed the equation

#y=-2/3x+b#

Use either points for x and y and solve for b

#8=-2/3(6)+b#

#8=-12/3+b#

#8=-4+b#

#b=12#

Plug b in

#y=-2/3x+12#

#4=-2/3(12)+b#

#4=-24/3+b#

#4=-8+b#

#b=12#

Plug b in

#y=-2/3x+12#

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Answer 2

Isaiah Anthony

The equation of the line passing through the points (6, 8) and (12, 4) is y = -0.5x + 11.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.