What is the equation of the line that passes through (3, -7) and (-2, 4)?
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The equation of the line passing through the points (3, -7) and (-2, 4) can be found using the point-slope formula.
First, find the slope (m) using the formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ).
Then, choose one of the points and plug it into the point-slope formula: ( y - y_1 = m(x - x_1) ).
Finally, simplify the equation to put it in slope-intercept form (y = mx + b) if needed.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you write an equation of a line with slope 2/3 and point is (8, -4)?
- How do you find the slope of a line parallel to #3x+5y=15#?
- How do you write an equation of a line given slope 1/3 and y-intercept (0, -6)?
- What is the equation of the line perpendicular to #y=15/4x # that passes through # (-2,7) #?

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