# What is the equation of the line that passes through #(0,-1)# and is perpendicular to the line that passes through the following points: #(8,-3),(1,0) #?

Hence, desired equation will be

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First, find the slope of the line passing through the points (8,-3) and (1,0):

m = (y2 - y1) / (x2 - x1) m = (0 - (-3)) / (1 - 8) m = 3 / (-7) m = -3/7

The line perpendicular to this one will have a slope that is the negative reciprocal of -3/7, which is 7/3.

Now, use the point-slope form of the equation of a line with the slope of 7/3 and the point (0,-1):

y - y1 = m(x - x1)

Substitute the values into the formula:

y - (-1) = (7/3)(x - 0)

Simplify:

y + 1 = (7/3)x

Subtract 1 from both sides:

y = (7/3)x - 1

So, the equation of the line passing through (0,-1) and perpendicular to the line passing through the points (8,-3) and (1,0) is y = (7/3)x - 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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