# What is the equation of the line that is normal to #f(x)= sqry(x-2) # at # x=5 #?

Equation of tangent is

graph{(x-2sqrt3y+1)(y-sqrt(x-2))=0 [0.81, 10.81, -0.56, 4.44]}

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The equation of the line that is normal to f(x) = sqrt(x-2) at x=5 is y = -2(x-5) + sqrt(5-2).

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