# What is the equation of the line that is normal to #f(x)= ln(x^2-x+1) #at # x= 1 #?

First, find the point the normal line will intercept.

To find the slope of the normal line, we must first find the slope of the tangent line. To do this, we need to find the function's derivative.

Use the chain rule:

graph{(y-ln(x^2-x+1))(y+x-1)=0 [-5.555, 8.49, -2.61, 4.41]}

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The equation of the line that is normal to f(x) = ln(x^2-x+1) at x = 1 is y = -2x + 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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