# What is the equation of the line that is normal to #f(x)=-e^x # at # x=-2 #?

By signing up, you agree to our Terms of Service and Privacy Policy

The equation of the line that is normal to f(x) = -e^x at x = -2 is y = 0.1353x + 0.2707.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you find #f'(4)# if #f(x)=2sqrt(2x)#?
- How do you find the equation of the tangent line to the curve #f(x) = x^2 + 2x#; at x=3, x=5?
- How do you find the derivative of #f (x) = 3x^5 + 4x# using the limit definition?
- What is the equation of the normal line of #f(x)= sqrt(e^(2x)-x^2)/(x-1)^2# at #x = 3#?
- Slope of a curve #y=x^2-3# at the point where #x=1#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7