# What is the equation of the line that is normal to #f(x)=-2x^3-3x^2+5x-2# at # x=1 #?

The gradient of the line is found by differentiation

So we have

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The equation of the line that is normal to f(x)=-2x^3-3x^2+5x-2 at x=1 is y = -1.

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