What is the equation of the line tangent to #f(x)=x tan^2x # at #x=pi/4#?
For the equation we need the slope of the tangent line and the point on the curve.
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The equation of the line tangent to f(x) = x tan^2x at x = pi/4 is y = 2x - pi/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the instantaneous velocity of an object moving in accordance to # f(t)= (sin2tcost,tant-sect ) # at # t=(13pi)/12 #?
- What is the slope of #f(x)=-e^x+2x# at #x=1#?
- How do you find the equation of tangent line to the curve #y=2x^2+4x-3# at the point (1,3)?
- Ho do I use the limit definition of derivative to find #f'(x)# for #f(x)=3x^2+x# ?
- What is the equation of the line that is normal to #f(x)=(2x-1)/e^x# at # x=1/2 #?

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