What is the equation of the line tangent to # f(x)=x + cos (x)# at # x=0 #?
Thus, the point of contact P of the tangent is (0, 1) at x = 0, f = 1.
At P, the tangent's slope is f' = 1+sin x = 1.
The tangent equation at P(0, 1) is now
graph{(x+cosx-y)(x-y+1.05)(x^2+(y-1)^2-.01)=0 [-5, 5, -2.5, 2.5]} graph{(x+cosx-y)(x-y+1.05)(x-y-1)(x^2+(y-1)^2-.01)=0 [-30, 30 -15, 15]}
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The equation of the line tangent to f(x)=x + cos(x) at x=0 is y = 1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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