What is the equation of the line tangent to #f(x)=(x-4)^2-x # at #x=-1#?
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The equation of the line tangent to f(x)=(x-4)^2-x at x=-1 is y = -2x - 1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the equation of the line that is normal to #f(x)=-2x^2+4x-2 # at # x=3 #?
- What is the equation of the normal line of #f(x)=x-sinx# at #x=pi/6#?
- How do you find the coordinates of the points on the curve #x^2-xy+y^2=9# where the tangent line is horizontal?
- How do you find the equation of the line tangent to #y=4x^3+12x^2+9x+7# at (-3/2,7)?
- How do you determine the values of x at which #sqrt(x^2 + 9)# is differentiable?

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