What is the equation of the line tangent to # f(x)=-(x-3)^2-5x-3# at # x=5#?
Equation of tangent is
graph{(9x+y-13)(y+(x-3)^2+5x+3)=0 [-10, 10.8, -60, 20]}
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The equation of the line tangent to f(x)=-(x-3)^2-5x-3 at x=5 is y = -4x + 14.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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