What is the equation of the line tangent to # f(x)=x^2- xcosx# at # x=0 #?
Y=-x
Finding the slope requires first obtaining f'(x)= 2x-[cosx - x sin x]; at x=0, f '(x)= -1; thus, the tangent passes through (0,0) and has a slope of -1; the tangent's equation would be y=-x.
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The equation of the line tangent to f(x)=x^2- xcosx at x=0 is y = -x.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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