# What is the equation of the line tangent to #f(x)=x^2 sin2x # at #x=pi/4#?

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The equation of the line tangent to f(x)=x^2 sin2x at x=pi/4 is y = (pi/4)^2 sin(2(pi/4)) + 2(pi/4) cos(2(pi/4))(x - pi/4).

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