# What is the equation of the line tangent to #f(x)= 3x^2 - 12x-5 # at #x=-1#?

To find a point on the tangent, evaluate f( -1)

By signing up, you agree to our Terms of Service and Privacy Policy

The equation of the line tangent to f(x) = 3x^2 - 12x - 5 at x = -1 is y = -6x - 8.

By signing up, you agree to our Terms of Service and Privacy Policy

- What is the equation of the line normal to # f(x)=sqrt(x)-e^(sqrtx)# at # x=1#?
- Find all tangent lines to the graph of #y = x^3# that pass through the point. #P(2, 4)#?
- How do you find the slope of the tangent line at point (2, 1) for #y=(x^2+1)#?
- What is the equation of the line normal to # f(x)=-sqrt((x+1)(x+3)# at # x=0#?
- How do you use the limit definition to find the derivative of #x/(sqrt(1-x^2)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7