What is the equation of the line tangent to # f(x)=2secx # at # x=pi/4#?
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The equation of the line tangent to f(x) = 2sec(x) at x = pi/4 is y = sqrt(2) + sqrt(2)(x - pi/4).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the equation of the line tangent to # f(x)=xsecx - xcosx # at # x=pi/3#?
- How do you find the average rate of change of #f(x) = 5x^2+2x-7# over the interval [5,7]?
- What is the equation of the tangent line of #f(x) =(e^(x^2)-x)(e^x-x^2)# at #x=2#?
- What is the equation of the normal line of #f(x)=e^(2x)-x^3# at #x=2#?

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