What is the equation of the line passing through #(97,26)# and #(10,34)#?

Answer 1

#8x+87y-3038=0#

To find the gradient, do rise/run.

= #(34-26)/(10-97)#
= #8/-87=-8/87#
The equation is now #y=-8/87x + c#

The sub one of the coordinates to find c.

#34=-8/87(10) +c#
or #34= -80/87+c#
or #c=-34+80/87#
or #c=(34xx87+80)/87=3038/87#

The full equation is:

#y=-8/87x + 3038/87#
or #8x+87y-3038=0#
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Answer 2

To find the equation of the line passing through the points (97, 26) and (10, 34), you would first calculate the slope using the formula: ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ), where ( (x_1, y_1) ) and ( (x_2, y_2) ) are the coordinates of the two points. Then, you would use the slope-intercept form of a line ( y = mx + b ) and one of the given points to solve for the y-intercept ( b ). Finally, you would write the equation using the found slope and y-intercept.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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