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What is the equation of the line passing through #(60,16)# and #(18,26)#?

Answer 1

Avery Alexander

#(y-16) = -5/21(x-60)#

First you determine the slope:

#(color(blue)(x_1),color(blue)(y_1)) = (60,16)#

#(color(red)(x_2),color(red)(y_2))=(18,26)#

#color(green)m =(color(red)(y_2)-color(blue)(y_1))/(color(red)(x_2)-color(blue)(x_1))#

#color(green)m =(color(red)(26)-color(blue)(16))/(color(red)(18)-color(blue)(60))=-5/21#

Now use the Point Slope form of a line:

#(y-color(blue)(y_1)) = color(green)m(x-color(blue)(x_1))#

#(y-color(blue)(16)) = color(green)(-5/21)(x-color(blue)(60))#

graph{(y-16) = -5/21(x-60) [-67, 93, -0.96, 79.04]}

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Answer 2

Hazel Anglin

To find the equation of the line passing through the points (60,16) and (18,26), first calculate the slope using the formula: m = (y2 - y1) / (x2 - x1). Then, use the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is one of the given points and m is the slope. Finally, simplify the equation to slope-intercept form, y = mx + b, if necessary.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.