# What is the equation of the line normal to # f(x)=xsqrtx-e^(sqrtx)# at # x=1#?

Now, find the derivative of the given function to find an equation for the slope of the tangent line:

Substitute x = 1 to find the slope of the tangent line at that point:

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The equation of the line normal to f(x) = xsqrt(x) - e^(sqrt(x)) at x = 1 is y = -2x + 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the equation of the tangent line of #f(x) =e^xlnx-x# at #x=2#?
- Consider the function #f(x) = absx# on the interval [-4, 6], how do you find the average or mean slope of the function on this interval?
- How do you find an equation of the tangent line to the curve at the given point #y=secx - 2cosx# and #(pi/3, 1)#?
- What is the equation of the tangent line of #f(x) = 3x^3+e^(-3x)-x# at #x=4#?
- What is the slope of the line normal to the tangent line of #f(x) = secx+sin(2x-(3pi)/8) # at # x= (11pi)/8 #?

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