What is the equation of the line normal to # f(x)=xsin(3x+pi/4)# at # x=pi/2#?
graph{(xsin(3x+.7854)-y)(0.3809x+y+0.5124)=0 [-40, 40, -20, 20]}
Uniform scale graphs.
graph{(xsin(3x+.7854)-y)(0.38x+y0.51)((x-1.5804)^2+(y+1.1107)^2-.01)=0 [0, 2, --100, 100]}
with zeros at x = 1/3(k-1/4)pi. k = 0, +-1, +-2, ... that have common
So, the equation to the normal at P is
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The equation of the line normal to f(x)=xsin(3x+pi/4) at x=pi/2 is y = -3x + 3pi/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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