# What is the equation of the line normal to # f(x)=sqrt(1/(x^2+2) # at # x=1#?

in simplifying the equation we get

We then apply the chain rule to get

Then we substitute in 1 for x to find the gradient of the tangent at x=1

Therefore by substituting the numbers/values into the point gradient formula, we'll find the equation of the normal. The point gradient formula is

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The equation of the line normal to f(x) = sqrt(1/(x^2+2)) at x = 1 is y = -2x + 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the equation of the line tangent to # f(x)=x^2+6x-5# at # x=3 #?
- What is the equation of the tangent line of #f(x) =((x-1)^3(x^2+2))/(e^x-1)^4# at #x=2#?
- What is the equation of the normal line of #f(x)=xln(3^(1/x))# at #x=0#?
- What are the x-values on the graph of #y= 1/x# where the graph is parallel to the line #y= -4/9x+7#?
- What is the equation of the normal line of #f(x)= x^3/(3x^2-2x)+6x# at #x = 2#?

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