# What is the equation of the line normal to #f(x)= -1/(5-x^2) # at #x=-3#?

Equation of line normal is

and equation of line normal is

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The equation of the line normal to f(x) = -1/(5-x^2) at x = -3 is y = -3x - 4.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the equation of the line normal to # f(x)=sqrt(1/(x+2) # at # x=-1#?
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- How do you find the equation of the line tangent to #y= -x^3+6x^2-5x# at (1,0)?
- How do you find the equations of both lines through point (2,-3) that are tangent to the parabola #y=x^2+x#?

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