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What is the equation of the circle with a center at #(3 ,1 )# and a radius of #1 #?

Answer 1

Noah Atkinson

#(x-3)^2+(y-1)^2=1#

The general form for the equation of a circle with a center at #(h,k)# and radius #r# is

#(x-h)^2+(y-r)^2=r^2#

We are aware of that

#(h,k)rarr(3,1)=>h=3,k=1# #r=1#

Consequently, the circle's equation is

#(x-3)^2+(y-1)^2=1^2#

or, slightly more simplified (squaring the #1#):

#(x-3)^2+(y-1)^2=1#

The circle displayed the following graph:

graph{(x-3)^2+(y-1)^2-1)(x-3)^2+(y-1)^2-.003)=0 [-2.007, 9.093, -1.096, 4.454]}

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Answer 2

Carson Arnold

The equation of the circle with a center at ((3, 1)) and a radius of (1) is:

[ (x - 3)^2 + (y - 1)^2 = 1^2 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.