What is the equation of the circle with a center at #(2 ,6 )# and a radius of #3 #?

Answer 1

The equation of the circle would be #(x - 2)^2 + (y - 6)^2 = 3^2#
or #(x - 2)^2 + (y - 6)^2 = 9#

The equations of the circle is
#(x - h)^2 + (y- k)^2 = r^2#
where h is the x of the center of the circle and k is the y of the center of the circle, and r is the radius.

(2,6) radus is 3

h = 2
k = 6
r = 3

plug in the values
#(x - 2)^2 + (y- 6)^2 = 3^2#
simplify
#(x + 4)^2 + (y- 6)^2 = 9#

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Answer 2

Parker Allen

The equation of the circle with a center at (2, 6) and a radius of 3 is: (x - 2)^2 + (y - 6)^2 = 3^2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.