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What is the equation of the circle with a center at #(2 ,-3 )# and a radius of #5 #?

Answer 1

Caroline Aucoin

#(x-2)^2+(y+3)^2=25#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(2,-3)# and the radius is #5#, we know that

#{(h=2),(k=-3),(r=5):}#

Consequently, the circle's equation is

#(x-2)^2+(y-(-3))^2=5^2#

This becomes easier to understand.

#(x-2)^2+(y+3)^2=25#

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Answer 2

Parker Allen

The equation of the circle with a center at (2, -3) and a radius of 5 is:

(x - 2)^2 + (y + 3)^2 = 25

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.