# What is the equation of the circle with a center at #(2 ,2 )# and a radius of #4 #?

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graph{[-6.67, 13.33, -3.08, 6.92]} = (x-2)^2 + (y-2)^2

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The equation of a circle with center ((h, k)) and radius (r) is given by:

[ (x - h)^2 + (y - k)^2 = r^2 ]

Substituting the given values, where the center is ((2, 2)) and the radius is (4), we have:

[ (x - 2)^2 + (y - 2)^2 = 4^2 ]

[ (x - 2)^2 + (y - 2)^2 = 16 ]

So, the equation of the circle is ( (x - 2)^2 + (y - 2)^2 = 16 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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