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What is the equation of a line with x intercept (-15/2,0) and y intercept (0,-3)?

Answer 1

Avery Alexander

#y=2/5x+3#

#(-15/2,0) and (0,3)#

you have the y=intercept of #3# so use the form:

#y=mx+b#

m = slope b = y-intercept

formula to find slope is:

#m = (y_2-y_1)/(x_2-x_1)#

#m = (3-0)/(0-(-15/2)) = 2/5#

#b=3#

#y=mx+b#

#y=2/5x+3#

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Answer 2

Julia Adams

To find the equation of a line given the x-intercept (-15/2, 0) and y-intercept (0, -3), you can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

First, find the slope (m) using the formula: m = (y₂ - y₁) / (x₂ - x₁) m = (-3 - 0) / (0 - (-15/2)) m = -3 / (15/2) m = -2/5

Then, plug the slope and the y-intercept into the equation: y = mx + b -3 = (-2/5)(0) + b b = -3

So, the equation of the line is: y = (-2/5)x - 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.