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What is the equation of a circle with its center at (10, -4) and a radius of 4?

Answer 1

Mason Adams

#x^2+y^2-20x+8y+100=0#

As we are aware,

The equation of the circle with center #(h,k) and# radius #r# ,is

#color(red)((x-h)^2+(y-k)^2=r^2#

We have, centre #(10,-4) and # radius #r=4#

So.

#(x-10)^2+(y-(-4))^2=(4)^2#

#(x-10)^2+(y+4)^2=16#

#x^2-20x+100+y^2+8y+16=16#

#x^2+y^2-20x+8y+100=0#

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Answer 2

Claire Akin

The equation of a circle with its center at ((h, k)) and a radius (r) is given by:

[ (x - h)^2 + (y - k)^2 = r^2 ]

Substituting the given values, the equation of the circle is:

[ (x - 10)^2 + (y + 4)^2 = 4^2 ]

Expanding, we get:

[ (x - 10)^2 + (y + 4)^2 = 16 ]

So, the equation of the circle is ( (x - 10)^2 + (y + 4)^2 = 16 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.