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What is the equation of a circle with a center at (-3, -4) and a radius of 3?

Answer 1

Caroline Aucoin

It is: #(x+3)^2+(y+4)^2=9#

The equatyion of a circle whose center is at #C=(a,b)# and radius is #r# is:

#(x-a)^2+(y-b)^2=r^2#

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Answer 2

Mason Adams

The equation of a circle with a center at ((-3, -4)) and a radius of 3 is given by the formula:

[ (x - h)^2 + (y - k)^2 = r^2 ]

Where ((h, k)) are the coordinates of the center of the circle, and (r) is the radius.

Substituting the given values, the equation becomes:

[ (x - (-3))^2 + (y - (-4))^2 = 3^2 ]

Simplify:

[ (x + 3)^2 + (y + 4)^2 = 9 ]

Therefore, the equation of the circle is ((x + 3)^2 + (y + 4)^2 = 9).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.