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What is the equation of a circle whose center is (4,-7) and a radius of 6?

Answer 1

Theodore Abad

#(x-4)^2+(y+7)^2=36#

#"the standard form of the equation of a circle is."#

#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#

#"where "(a,b)" are the coordinates of the centre and r"# #"is the radius"#

#"here "(a,b)=(4,-7)" and "r=6#

#(x-4)^2+(y-(-7))=6^2#

#rArr(x-4)^2+(y+7)^2=36larrcolor(red)"equation of circle"#

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Answer 2

Noah Atkinson

The equation of a circle with center ( (h, k) ) and radius ( r ) is given by:

[ (x - h)^2 + (y - k)^2 = r^2 ]

Given that the center of the circle is ( (4, -7) ) and the radius is 6, substitute these values into the equation:

[ (x - 4)^2 + (y - (-7))^2 = 6^2 ]

Simplify this equation to get the equation of the circle.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.