What is the equation in point-slope form of the line given (3,7); m=0?

Answer 1

The line is #y=7#.

The line passes through the points #(3,7)# and has a slope of #m=0#.

We know that the slope of a line is given by:

#m=(y_2-y_1)/(x_2-x_1)#

And so,

#(y_2-y_1)/(x_2-x_1)=0#
#:.x_2!=x_1,y_2=y_1#
Choosing a y-coordinate, we see that it passes through #(3,7)#, and so #y_2=y_1=7#.
Therefore, the line is #y=7#.

Here is a graph of the line:

graph{y=0x+7 [-4.54, 18.89, -0.84, 10.875]}

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Answer 2

The equation in point-slope form of the line given the point (3,7) and slope (m=0) is (y - 7 = 0 \cdot (x - 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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