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What is the equation in point-slope form of the line given (-2,3); m=-1?

Answer 1

You can use the relationship: #y-y_0=m(x-x_0)# With: #m=-1# #x_0=-2# #y_0=3# If you have difficulty have a look at the solution below. . . . . . . . . Solution: #y-3=-1(x+2)#

That can also be written as: #y=-x-2+3# #y=-x+1#

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Answer 2

Avery Alexander

The answer is #y-3=-1(x+2)#.

Determine the point-slope form of a line passing through the point #(-2,3)# with slope, #m# of #-1#.

Generic point-slope form is #y-y_1=m(x-x_1)# .

For point #(-2,3)#, #y_1=3#, #x_1=-2#

Point-slope for given point and slope.

#y-3=-1(x-(-2))# =

#y-3=-1(x+2)#

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Answer 3

Savannah Anderson

The equation in point-slope form of the line with the point (-2,3) and slope m = -1 is:

y - 3 = -1(x - (-2))

Simplified:

y - 3 = -1(x + 2)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.