What is the equation in point slope form for the line passing through (10,-9) with slope m=-2?
The equation is y = -2x + 11
Use the general form for a linear equation, y = mx + c You have been given m = -2 and you have the point (10, -9) so you know that when y = -9 then x = 10 Substitute these into y = mx + c to get -9 = (-2 * 10) + c -9 = -20 + c and solve it to find c
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The point-slope form of a line is given by the equation (y - y_1 = m(x - x_1)), where ((x_1, y_1)) is a point on the line, and (m) is the slope.
Given the point ((10, -9)) and the slope (m = -2), the equation of the line in point-slope form is:
[y - (-9) = -2(x - 10).]
Simplifying, we get:
[y + 9 = -2(x - 10).]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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