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What is the empirical formula for the compound consisting of 63% manganese and 37% oxygen by mass?

Answer 1

#MnO_2#

As with all empirical formula calculations, a starting mass of #100# #g# is assumed.

There are thus #(63*g)/(54.94*g*mol^-1)# #=# #1.15*mol# #Mn#, and #(37*g)/(15.999*g*mol^-1)# #=# #2.132*mol# with respect to #O#.

Now, we simply divide thru by the LOWEST molar quantity, which here is the metal to give an empirical formula of #MnO_2", manganese(IV) oxide"#.

The simplest whole number ratio that defines the constituent atoms of a species is, as usual, the empirical formula.

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Answer 2

Avery Adams

The empirical formula for the compound consisting of 63% manganese and 37% oxygen by mass is MnO2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.