Home > Chemistry > Electron Configuration

What is the electron configuration (arrangement) by spdf notation of a sodium ion?

Answer 1

Olivia Anton

#1s^2 2s^2 2p^6#

To become the sodium ion, or to take on the configuration of neon, sodium loses one electron from its outermost shell.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Avery Adams

#1s^2\2s^2\2p^6# or just #[Ne]#

A neutral sodium atom has an electron configuration of #[Ne]3s^1#.

Since it has #11# electrons, it would want to lose one electron to remove its third shell, while keeping the other #2# electron shells full. So, in a sodium ion, it becomes #Na^+# and has only #10# electrons.

So, it will remove #1# electron, and lose its #3s# orbital. The electron configuration therefore just becomes #[Ne]# or if you want the full configuration, it is #1s^2\2s^2\2p^6#.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 3

Cooper Adams

The electron configuration of a sodium ion (Na+) is 1s^2 2s^2 2p^6.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.