What is the electric current produced when a voltage of #9 V# is applied to a circuit with a resistance of #36 Omega#?
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The electric current produced in the circuit can be calculated using Ohm's law:
[ I = \frac{V}{R} ]
Where:
- ( I ) = electric current (in amperes)
- ( V ) = voltage (in volts)
- ( R ) = resistance (in ohms)
Plugging in the values:
[ I = \frac{9 , \text{V}}{36 , \Omega} ]
[ I = \frac{1}{4} , \text{A} ]
So, the electric current produced is ( \frac{1}{4} ) ampere or 0.25 amperes.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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