# What is the electric current produced when a voltage of #8 V# is applied to a circuit with a resistance of #48 Omega#?

Current I= E/R where E is voltage and R Resistance.

Answer 8/48= 0.166 amps.

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The electric current produced can be calculated using Ohm's law, which states that the current ((I)) is equal to the voltage ((V)) divided by the resistance ((R)).

(I = \frac{V}{R})

Substituting the given values:

(I = \frac{8 , \text{V}}{48 , \Omega})

(I = \frac{1}{6} , \text{A})

(I = 0.1667 , \text{A})

Therefore, the electric current produced when a voltage of 8 V is applied to a circuit with a resistance of 48 Ω is 0.1667 A.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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