What is the electric current produced when a voltage of #24 V# is applied to a circuit with a resistance of #32 Omega#?

I=Current E voltage R=resistance. 24/32= current.75 ampere.

The electric current produced when a voltage of 24 V is applied to a circuit with a resistance of 32 Ω can be calculated using Ohm's Law: ( I = \frac{V}{R} ). Substituting the given values, we get ( I = \frac{24 , \text{V}}{32 , \Omega} = 0.75 , \text{A} ). Therefore, the electric current produced is 0.75 amps.

To calculate the electric current produced when a voltage of 24 V is applied to a circuit with a resistance of 32 Ω, we can use Ohm's Law, which states:

[ I = \frac{V}{R} ]

Where:

• ( I ) represents the electric current in Amperes (A)
• ( V ) represents the voltage in Volts (V)
• ( R ) represents the resistance in Ohms (Ω)

Given that ( V = 24 ) V and ( R = 32 ) Ω, we can substitute these values into the formula:

[ I = \frac{24}{32} ]

[ I = 0.75 ]

Therefore, the electric current produced when a voltage of 24 V is applied to a circuit with a resistance of 32 Ω is ( 0.75 ) Amperes.