What is the dot product of #<-6,4,2 > # and #<7,1,0 > #?

Answer 1

Layla Ahmed

The dot product is #=-38#

The dot product of #2# vectors

#veca= < a,b, c> #

additionally

#vecb= < d,e, f> #

#veca . vecb =< a,b, c> . < d,e, f>#

#=(axxd)+(bxxe)+(cxxf)#

Thus,

The product that dots are

#=<-6, 4, 2> . <7,1,0>#

#=(-6xx7)+(4xx1)+(2xx0)#

#=-42+4+0#

#=-38#

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Answer 2

Adam Arnold

The dot product of the vectors <-6, 4, 2> and <7, 1, 0> is calculated by multiplying corresponding components and then summing the results. So, (-6 * 7) + (4 * 1) + (2 * 0) = -42 + 4 + 0 = -38. Therefore, the dot product is -38.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the dot product of #&lt;-6,4,2 &gt; # and #&lt;7,1,0 &gt; #?

What is the dot product of #<-6,4,2 > # and #<7,1,0 > #?