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What is the domain of #f(x) = sqrt(x^2-144)#?

Answer 1

Julia Adams

#x >= 12 and x <= -12#

#x^2 - 144 >=0# or the value under the radical in imaginary:

#x^2 >=144#

#x >= +-sqrt144#

#x >= +-12#

#x >= 12 and x <= -12#

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Answer 2

Savannah Anderson

The domain of (f(x) = \sqrt{x^2 - 144}) is all real numbers where the expression under the square root is non-negative. Therefore, the domain is ((-∞, -12] ∪ [12, ∞)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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