What is the domain and range of # y = sqrt(9 + x)#?
By signing up, you agree to our Terms of Service and Privacy Policy
The domain of the function ( y = \sqrt{9 + x} ) is all real numbers where ( 9 + x ) is non-negative, so the domain is ( x \geq -9 ). The range is all real numbers where ( y ) is non-negative, so the range is ( y \geq 0 ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you find the domain and range of #f(x) = x^3 + 5#?
- How do you find the domain of #p(x)=x^2+4#?
- How do you solve #(x - 3) - 5x = - 3( x + 3)#?
- Jim went bowling with some friends. It cost him $2 to rent bowling shoes and $3.50 per game of bowling. He spent a total of $16. How do you write and solve an equation to determine how many games he bowled?
- How do you find #h(4)# given #h(n)=n^3+6n#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7