What is the domain and range of #ln(x^2+1)#?
Domain is
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The domain of ln(x^2 + 1) is all real numbers such that x^2 + 1 is greater than zero, or x^2 + 1 > 0. Solving this inequality yields the domain as (-∞, ∞). The range of ln(x^2 + 1) is all real numbers, or (-∞, ∞).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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