# What is the domain and range of #ln(x^2+1)#?

Domain is

By signing up, you agree to our Terms of Service and Privacy Policy

The domain of ln(x^2 + 1) is all real numbers such that x^2 + 1 is greater than zero, or x^2 + 1 > 0. Solving this inequality yields the domain as (-∞, ∞). The range of ln(x^2 + 1) is all real numbers, or (-∞, ∞).

By signing up, you agree to our Terms of Service and Privacy Policy

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7