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What is the domain and range of #g(x)=(1-x^2)#?

Answer 1

Julia Adams

domain would be (-infinity to infinity)

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Answer 2

Ethan Adkins

The domain would be unlimited, as there are no 'forbidden' values for #x# (no fractions, no roots).
Domain #=(-oo,+oo)#

For the range we observe that the maximum value of #g(x)# happens when #x=0# (which means the least to subtract from 1). Any other value of #x# would make #x^2>0->g(x)<1# Range #=(-oo,1]#

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Answer 3

Isaiah Anthony

The domain of the function ( g(x) = 1 - x^2 ) is all real numbers.

The range of the function ( g(x) = 1 - x^2 ) is the set of all real numbers less than or equal to 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.