What is the distance between A(-1,-3) and point B(5,5)?

Answer 1

The distance between points A(-1,-3) and B(5,5) is 10 units.

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Answer 2

#10#

You are going to have to use the distance formula. That states that the distance between two points is #sqrt((x_2-x_1)^2 + (y_2-y_1)^2)# (it basically makes a triangle with side lengths #(x_2-x_1)# and #(y_2-y_1)# and then uses the Pythagorean Theorem.

For more information on where the distance formula came from, see this website.

We can just plug into this equation to get the distance. #sqrt((x_2-x_1)^2 + (y_2-y_1)^2)# =#sqrt((5-(-1))^2 + (5-(-3))^2)# =#sqrt((6)^2 + (8)^2)# =#sqrt(36+64)# =#sqrt(100)# =#10#
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Answer 3

To find the distance between points ( A(-1, -3) ) and ( B(5, 5) ), you can use the distance formula:

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Substituting the coordinates of the points:

[ d = \sqrt{(5 - (-1))^2 + (5 - (-3))^2} ]

[ d = \sqrt{(5 + 1)^2 + (5 + 3)^2} ]

[ d = \sqrt{(6)^2 + (8)^2} ]

[ d = \sqrt{36 + 64} ]

[ d = \sqrt{100} ]

[ d = 10 ]

So, the distance between points ( A(-1, -3) ) and ( B(5, 5) ) is 10 units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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