# What is the distance between #(-6 , pi/2 )# and #(5, pi/12 )#?

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To find the distance between two points in a coordinate plane, we use the distance formula: ( \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ).

Given the coordinates (-6, π/2) and (5, π/12), we can plug these values into the formula:

( \sqrt{(5 - (-6))^2 + (\frac{\pi}{12} - \frac{\pi}{2})^2} )

( = \sqrt{(5 + 6)^2 + (\frac{\pi}{12} - \frac{6\pi}{12})^2} )

( = \sqrt{11^2 + (\frac{-5\pi}{12})^2} )

( = \sqrt{121 + \frac{25\pi^2}{144}} )

Thus, the distance between the points (-6, π/2) and (5, π/12) is ( \sqrt{121 + \frac{25\pi^2}{144}} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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