What is the distance between #(–3, –2)# and #(5, 2)#?
The distance between (–3, –2) and (5, 2) is 10 units.
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The distance,
#r = sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)#
It is an application of Pythagoras Theorem.
Therefore, the distance between
#sqrt((-3 - 5)^2 + (-2 - 2)^2) = sqrt(64+16)#
#= sqrt80#
#= 4sqrt5#
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#color(blue)((-3,-2)and(5,2)#
Use the distance formula
So,
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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