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What is the distance between #(–2, 2, 6) # and #(–1, 1, 3) #?

Answer 1

Kennedy Adams

The distance between (–2, 2, 6) and (–1, 1, 3) is √10.

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Answer 2

Eva Adamson

The distance between to points #(x_1, x_2, x_3)# and #(y_1, y_2, y_3)# in the 3-dimensional space is #sqrt((x_1-y_1)^2+ (x_2-y_2)^2+ (x_3-y_3)^2#

Now simply replacing #(x_1, x_2, x_3)# and #(y_1, y_2, y_3)# by the values given we have:

#sqrt((-2+1)^2+ (2-1)^2+ (6-3)^2)=sqrt((-1)^2+ (1)^2+ (3)^2)=sqrt(11)#

which is the distance

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Answer 3

Genesis Allen

Distance between #(-2,2,6)# and #(-1,1,3)# is #sqrt11=3.317#

The distance between two points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence distance between #(-2,2,6)# and #(-1,1,3)# is

#sqrt(((-1)-(-2))^2+(1-2)^2+(3-6)^2)#

= #sqrt((-1+2)^2+(-1)^2+(-3)^2)#

= #sqrt(1^2+1+9)#

= #sqrt11#

= #3.317#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.