What is the derivative of #y=tan(x)/x#?
In this problem, we can assign the following values to the variables in the quotient rule:
If we plug these values into the quotient rule, we get the final answer:
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To find the derivative of ( y = \frac{\tan(x)}{x} ), we can use the quotient rule.
Let ( u = \tan(x) ) and ( v = x ).
Now, ( \frac{du}{dx} = \sec^2(x) ) (derivative of ( \tan(x) )) and ( \frac{dv}{dx} = 1 ).
Applying the quotient rule ( \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{u'v - uv'}{v^2} ), we get:
( \frac{dy}{dx} = \frac{(x\sec^2(x) - \tan(x)) - (\tan(x))(1)}{x^2} )
( \frac{dy}{dx} = \frac{x\sec^2(x) - \tan(x) - \tan(x)}{x^2} )
( \frac{dy}{dx} = \frac{x\sec^2(x) - 2\tan(x)}{x^2} )
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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