# What is the derivative of #y=ln(sec(x)+tan(x))#?

Full explanation:

Similarly, if we follow for the problem, then

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To find the derivative of ( y = \ln(\sec(x) + \tan(x)) ), you would use the chain rule. The derivative is:

[ \frac{d}{dx}\ln(\sec(x) + \tan(x)) = \frac{1}{\sec(x) + \tan(x)} \cdot (\sec(x)\tan(x) + \sec^2(x)) ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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